What is the equation of the line that passes through (1, 5) and (2, 14) in slope-intercept form?

To find the equation of the line that passes through the points (1, 5) and (2, 14), we first need to determine the slope (m) of the line using the formula:

m = (y2 – y1) / (x2 – x1)

In our case, (x1, y1) is (1, 5) and (x2, y2) is (2, 14). Plugging in these values, we get:

m = (14 – 5) / (2 – 1) = 9 / 1 = 9

Now that we have the slope, we can use the slope-intercept form of a line, which is:

y = mx + b

Next, we need to find the y-intercept (b). We can use one of the points to help us with this. Let’s use the point (1, 5):

5 = 9(1) + b

Solving for b:

5 = 9 + b

b = 5 – 9 = -4

Now we can write the equation of the line:

y = 9x – 4

This is the equation of the line in slope-intercept form that passes through the points (1, 5) and (2, 14).

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