To find the equation of the line that passes through the points (0, 9) and (3, 0), we can start by calculating the slope of the line using the formula:
slope (m) = (y2 – y1) / (x2 – x1)
Here, (x1, y1) = (0, 9) and (x2, y2) = (3, 0).
Now substituting these values into the slope formula, we get:
m = (0 – 9) / (3 – 0) = -9 / 3 = -3
Next, we can use the point-slope form of the equation of a line, which is:
y – y1 = m(x – x1)
Using point (0, 9) and the slope -3:
y – 9 = -3(x – 0)
Now, simplify this equation:
y – 9 = -3x
Rearranging gives us:
y = -3x + 9
So, the equation of the line that passes through the points (0, 9) and (3, 0) is:
y = -3x + 9