To calculate the molar mass of silver phosphate (Ag3PO4), we need to determine the atomic masses of each element in the compound and then sum them appropriately.
1. **Identify the elements and their atomic masses:**
– Silver (Ag): approximately 107.87 g/mol
– Phosphorus (P): approximately 30.97 g/mol
– Oxygen (O): approximately 16.00 g/mol
2. **Count the number of each atom in the formula:**
– Ag: 3 atoms
– P: 1 atom
– O: 4 atoms
3. **Calculate the total mass contributed by each element:**
– For Silver: 3 × 107.87 g/mol = 323.61 g/mol
– For Phosphorus: 1 × 30.97 g/mol = 30.97 g/mol
– For Oxygen: 4 × 16.00 g/mol = 64.00 g/mol
4. **Add these values together to find the molar mass of Ag3PO4:**
323.61 g/mol (Ag) + 30.97 g/mol (P) + 64.00 g/mol (O) = 418.58 g/mol
Hence, the correct molar mass of Ag3PO4 is approximately 418.58 g/mol.