What is the bond order of Be2? Express the bond order numerically.

The bond order of beryllium dimers (Be2) can be determined using molecular orbital theory. In Be2, each beryllium atom has 4 electrons in its outer shell, leading to a total of 8 valence electrons for the molecule.

When these electrons are placed in molecular orbitals, the configuration can be represented as follows:

  • σ1s2
  • σ*1s2
  • σ2s2
  • σ*2s0

In this configuration:

  • Bonding electrons (total): 2 (from σ2s)
  • Antibonding electrons (total): 2 (from σ*1s)

To calculate the bond order, we use the formula:

Bond Order = (Number of Bonding Electrons – Number of Antibonding Electrons) / 2

Plugging in the values:

Bond Order = (2 – 2) / 2 = 0

Therefore, the bond order of Be2 is 0, indicating that this molecule does not have a stable bond and is not found in nature.

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