What is the angular diameter of the Moon at perigee?

To find the angular diameter of the Moon at perigee, we can use the formula for angular diameter:

Angular Diameter (in degrees) = (Diameter of the object / Distance to the object) * (180 / π)

Given:

  • Diameter of the Moon = 3,474 km
  • Distance from the Earth to the Moon at perigee = 362,399 km

Let’s plug these values into the formula:

Angular Diameter = (3,474 km / 362,399 km) * (180 / π)

Now, calculating the values:

First, calculate the fraction:

  • 3,474 / 362,399 = 0.009605

Then multiply by (180 / π):

  • Angular Diameter ≈ 0.009605 * 57.2958 ≈ 0.5506 degrees

Next, to convert the decimal into degrees and arc minutes:

  • 0.5506 degrees = 0 degrees and (0.5506 * 60) arc minutes
  • 0.5506 * 60 ≈ 33.036 arc minutes

Therefore, the angular diameter of the Moon at perigee is approximately:

  • 0 degrees and 33 arc minutes.

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