What is an equation for a sine curve with amplitude 2 and period 4 pi radians?

The equation of a sine curve can be formulated with parameters that define its amplitude and period. In this case, we are looking for a sine function with an amplitude of 2 and a period of 4π radians.

The general form of the sine function is:

y = A * sin(B(x - C)) + D

Where:

  • A is the amplitude of the wave,
  • B affects the period of the wave,
  • C is the horizontal shift, and
  • D is the vertical shift.

In our case:

  • The amplitude A is 2, so we have A = 2.
  • The period P is given by the formula P = 2π/B. We want the period to be 4π, so:
4π = 2π/B

Solving for B gives:

B = 2π/(4π) = 1/2

Now, substituting these values into the sine function, we get:

y = 2 * sin((1/2)x)

This is the equation of the sine curve with an amplitude of 2 and a period of 4π radians. The equation can also be written as:

y = 2 * sin(0.5x)

And that gives us the sine curve we were looking for!

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