To determine the amount of oxygen gas required to completely react with 3 kg of nitrogen gas, we first need to look at the balanced chemical equation for the reaction between nitrogen (N2) and oxygen (O2) to form nitrogen dioxide (NO2):
N2 + 2O2 → 2NO2
This equation tells us that one mole of nitrogen gas reacts with two moles of oxygen gas. To find out how much oxygen gas is needed for 3 kg of nitrogen gas, we need to follow these steps:
- Convert the mass of nitrogen gas to moles. The molar mass of nitrogen (N2) is approximately 28 g/mol.
- Calculate moles of nitrogen gas in 3 kg:
3 kg = 3000 g
Moles of N2 = Mass (g) / Molar Mass (g/mol) = 3000 g / 28 g/mol ≈ 107.14 moles of N2
- Use the stoichiometry from the balanced equation to find moles of oxygen gas required:
According to the equation, for every mole of nitrogen gas, 2 moles of oxygen gas are needed:
107.14 moles of N2 × 2 = 214.28 moles of O2
- Convert moles of oxygen gas to grams. The molar mass of oxygen (O2) is approximately 32 g/mol.
Mass of O2 = Moles × Molar Mass
Mass of O2 = 214.28 moles × 32 g/mol ≈ 6857 g
This is equivalent to approximately 6.86 kg of oxygen gas.
In conclusion, to completely react with 3 kg of nitrogen gas, you would need about 6.86 kg of oxygen gas.