To find the quotient of the polynomial 2x³ + 3x + 22 divided by x – 2 using synthetic division, we first identify the coefficients of the polynomial:
- 2 (for x³)
- 0 (for x², which is missing)
- 3 (for x)
- 22 (constant)
We set up synthetic division by using the root of the divisor x – 2, which is 2. Next, we write the coefficients:
2 0 3 22
| 2
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Now, we proceed with synthetic division:
- Bring down the 2.
- Multiply 2 (the number we brought down) by 2 (the divisor root) to get 4 and add it to 0 (the next coefficient) to get 4.
- Multiply 4 by 2 to get 8 and add it to 3 to get 11.
- Multiply 11 by 2 to get 22 and add it to 22 (the last coefficient) to get 44.
The results of these calculations yield the coefficients of the quotient polynomial and the remainder:
2 4 11
R: 44
This means the quotient polynomial is 2x² + 4x + 11 and the remainder is 44.
Thus, the final answer can be expressed as:
2x² + 4x + 11 with a remainder of 44.