To perform synthetic division on the polynomial 2x³ + 10x² + 3x, we must first identify what we are dividing by. For this example, let’s assume we are dividing by (x – 1). The first step is to write down the coefficients of the polynomial:
- 2 (for x³)
- 10 (for x²)
- 3 (for x)
- 0 (for the constant term, since there is no constant)
Now, we set up our synthetic division:
1 | 2 10 3 0 | 2 12 15 ------------------- 2 12 15 15
Here’s a step-by-step explanation of the process:
- Bring down the leading coefficient (2) straight down.
- Multiply it by the divisor’s root (1) and add it to the next coefficient (10): 1 * 2 + 10 = 12.
- Repeat this process: multiply 12 by 1 and add to 3: 1 * 12 + 3 = 15.
- Finally, multiply 15 by 1 and add to 0: 1 * 15 + 0 = 15.
The result of our synthetic division shows that the quotient is 2x² + 12x + 15 and the remainder is 15. Therefore, the final result of dividing 2x³ + 10x² + 3x by (x – 1) is:
Quotient: 2x² + 12x + 15
Remainder: 15