To determine the stability of He22+ and He2+, we can analyze their electronic configurations using Molecular Orbital Theory.
First, let’s establish the molecular orbital diagrams for both ions.
For He2+:
- There are 2 helium atoms. Each helium atom has 2 electrons, giving a total of 4 electrons in neutral He2.
- Removing one electron for He2+ leaves us with 3 electrons.
The molecular orbitals fill in the following order for He2:
- σ1s (2 electrons)
- σ1s− (1 electron)
So, the electron configuration for He2+ is: σ1s2 σ1s−1. Since we have 2 electrons in the bonding orbital and 1 in the antibonding orbital, this molecule has a net bond order of
(2 – 1)/2 = 0.5.
For He22+:
- Removing two electrons for He22+ leaves us with 2 electrons.
The molecular orbitals fill similarly:
- σ1s (2 electrons)
So, the electron configuration for He22+ is: σ1s2. This gives a net bond order of
(2 – 0)/2 = 1.
Comparison of Stability:
A higher bond order indicates greater stability. Therefore:
- He22+ has a bond order of 1.
- He2+ has a bond order of 0.5.
Based on bond order, He22+ is more stable than He2+. This is primarily because He22+ has a complete bonding orbital with no occupancy of antibonding orbitals, leading to a stronger bond. In contrast, He2+ has an electron in an antibonding orbital, which reduces its stability.