In the compound PbO2, lead (Pb) is the cation and oxygen (O) is the anion. To determine the charge on the lead cation, we first note that the oxide ion (O2-) has a charge of -2.
Since there are two oxide ions in PbO2, the total negative charge from the oxygens is:
Total Negative Charge = 2 (from O2-) = 2 x -2 = -4
To achieve electrical neutrality in the compound, the total positive charge from the lead cation must exactly balance the total negative charge. Therefore, the charge on the lead cation must be +4. This is because:
Positive Charge from Pb = -Total Negative Charge
Positive Charge from Pb = +4 (to balance the -4 from the two O2- ions)
Thus, the charge on the cation (lead, Pb) in PbO2 is +4, and the correct name of the compound is lead(IV) oxide.