To find the third number in a sequence of 6 consecutive integers that sum up to 519, we can start by letting the first integer be represented as x. This means the integers can be expressed as:
x, x + 1, x + 2, x + 3, x + 4, x + 5
Now, we can set up the equation for their sum:
x + (x + 1) + (x + 2) + (x + 3) + (x + 4) + (x + 5) = 519
This simplifies to:
6x + 15 = 519
Next, we isolate x:
6x = 519 – 15
6x = 504
x = 504 / 6
x = 84
Now that we have the first integer, we can find the third integer in the sequence:
x + 2 = 84 + 2 = 86
Therefore, the third number in this sequence is 86.