The quadratic equation 2x² + 4x + 12 = 0 has?

The quadratic equation 2x² + 4x + 12 = 0 has no real solutions.

To understand why, we can use the quadratic formula, which is given by:

x = (-b ± √(b² – 4ac)) / 2a

Here, a = 2, b = 4, and c = 12. We first need to calculate the discriminant, which is b² – 4ac.

Calculating the discriminant:

b² = 4² = 16

4ac = 4 * 2 * 12 = 96

Now, substituting these values into the discriminant:

Discriminant = 16 – 96 = -80

Since the discriminant is negative (-80), it indicates that there are no real solutions to this equation. Instead, there will be two complex solutions. This means the quadratic graph does not intersect the x-axis.

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