Solve the system of equations 2r + 2s = 50 and 2r + s = 17

To solve the system of equations, we have:

• Equation 1: 2r + 2s = 50
• Equation 2: 2r + s = 17

We can start with Equation 2. Let’s isolate s in terms of r:

   2r + s = 17
   s = 17 - 2r

Now, we can substitute this expression for s in Equation 1:

   2r + 2(17 - 2r) = 50
   2r + 34 - 4r = 50
   -2r + 34 = 50
   -2r = 50 - 34
   -2r = 16
   r = -8

Now that we have r, we can substitute r = -8 back into our expression for s:

   s = 17 - 2(-8)
   s = 17 + 16
   s = 33

So, the solution to the system of equations is:

• r = -8
• s = 33

In conclusion, the values of r and s that satisfy both equations are r = -8 and s = 33.