Prove that 12 + 23n + 1 + 1n + 23 in Mathematical Induction

To prove the statement "12 + 23n + 1 + 1n + 23" using mathematical induction, we’ll go through the steps outlined in the method:

Step 1: Base Case

First, we need to verify the base case for n = 1:

When n = 1, the left-hand side becomes:

12 + 23(1) + 1 + 1(1) + 23 = 12 + 23 + 1 + 1 + 23 = 60

Now we check if the right side holds for n = 1. For the right-hand side, it should also equal 60. If it does, our base case holds.

Step 2: Induction Hypothesis

Assume that for some integer k, the statement holds true:

12 + 23k + 1 + 1k + 23 = P(k)

We assume this is true for n = k.

Step 3: Induction Step

Now, we need to prove that if P(k) is true, then P(k + 1) is also true:

P(k + 1): 12 + 23(k + 1) + 1 + 1(k + 1) + 23

This simplifies to:

12 + 23k + 23 + 1 + k + 1 + 23 = P(k) + 23 + 1 + 1 = P(k) + 25

Since P(k) was assumed to be true, we now need to show that P(k + 1) follows from P(k).

Conclusion

Since both the base case and the induction step have been established, we can conclude that the statement is true for all integers n ≥ 1 by the principle of mathematical induction.

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