My number has 2 hundreds; the tens digit is 9 more than the ones digit.

To solve this riddle, let’s break down the information given about the number. We know that the number has two hundreds, which means it can be represented in the form of 2XX, where X represents the tens and ones digits.

The next piece of information tells us that the tens digit is 9 more than the ones digit. If we denote the ones digit as Y, then the tens digit, based on the information given, would be Y + 9.

However, the digits can only range from 0 to 9. This means that there are limitations on Y. If we check the math:

  • If Y = 0, then the tens digit would be 0 + 9 = 9.
  • If Y = 1, then the tens digit would be 1 + 9 = 10 (not a valid digit).

So, the only valid choice for the ones digit, Y, is 0. Therefore, the tens digit will be 9.

Thus, the number can be concluded as 290, because it has two hundreds (200) and the tens digit (9) is indeed 9 more than the ones digit (0).

In summary, the number is 290.

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