Let f(x) = 8x³ + 28x + 61 and g(x) = 2x + 5. Find f(g(x)).

To find f(g(x)), we first need to understand what each function represents.

The function f(x) is given as:

f(x) = 8x³ + 28x + 61

And the function g(x) is:

g(x) = 2x + 5

Now, to find f(g(x)), we will substitute g(x) into the function f. This means wherever we see x in f(x), we will replace it with g(x).

Thus, we have:

f(g(x)) = f(2x + 5)

Now, we replace x in f(x):

f(2x + 5) = 8(2x + 5)³ + 28(2x + 5) + 61

This requires us to compute (2x + 5)³:

(2x + 5)³ = (2x + 5)(2x + 5)(2x + 5)

Using the binomial theorem, we can expand (2x + 5)³:

(2x)³ + 3(2x)²(5) + 3(2x)(5)² + (5)³ = 8x³ + 60x² + 150x + 125

Now substituting (2x + 5)³ back into f:

f(2x + 5) = 8(8x³ + 60x² + 150x + 125) + 28(2x + 5) + 61

Calculating this step-by-step:

8(8x³ + 60x² + 150x + 125) = 64x³ + 480x² + 1200x + 1000

Next:

28(2x + 5) = 56x + 140

So, summing it all together:

f(2x + 5) = (64x³ + 480x² + 1200x + 1000) + (56x + 140) + 61

Combining like terms:

f(2x + 5) = 64x³ + 480x² + (1200x + 56x) + (1000 + 140 + 61)

This gives us:

f(2x + 5) = 64x³ + 480x² + 1256x + 1201

Therefore, the result of f(g(x)) is:

f(g(x)) = 64x³ + 480x² + 1256x + 1201

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