This statement is true. The fluoride ion (F–) is indeed larger than the neutral fluorine atom (F).
When an atom gains an electron to form an anion, its overall size increases. This is because the addition of an electron increases electron-electron repulsion in the electron cloud. In the case of fluoride, the extra electron results in a larger electron cloud relative to the number of protons in the nucleus, leading to a greater ionic radius.
On the other hand, the neutral fluorine atom has no additional electron and thus retains a smaller size due to greater effective nuclear charge acting on its existing electrons. As a result, the size of the F– ion is greater than that of the neutral F atom.