True. In a geometric sequence, each term is obtained by multiplying the previous term by a constant ratio. Depending on the value of this ratio, the previous term a(n-1) can indeed be smaller than the current term a(n).
For instance, if the common ratio is greater than 1, the terms will increase, making a(n-1) smaller than a(n). However, if the common ratio is between 0 and 1, the terms would decrease, and a(n-1) would be larger than a(n). Therefore, the relationship between these terms entirely depends on the ratio used in the sequence, but it is possible for a(n-1) to be smaller than a(n).