If x varies jointly as y and z and x = 8 when y = 4 and z = 9, find z when x = 16 and y = 6.

To solve the problem, we start with the relationship given by the variation statement. Since x varies jointly as y and z, we can express this as:

x = k * y * z

where k is the constant of variation.

We know that x = 8 when y = 4 and z = 9. We can use these values to find k:

8 = k * 4 * 9

Calculating the right side:

8 = k * 36

To find k, we divide both sides by 36:

k = 8 / 36 = 2 / 9

Now that we have the value of k, we can use this to find z when x = 16 and y = 6. We plug in the known values into the variation equation:

16 = (2 / 9) * 6 * z

First, calculate (2 / 9) * 6:

(2 / 9) * 6 = 12 / 9 = 4 / 3

Now we substitute this back into the equation:

16 = (4 / 3) * z

To solve for z, multiply both sides by (3 / 4):

z = 16 * (3 / 4) = 12

Therefore, when x = 16 and y = 6, z is equal to 12.

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