If f(x) = 2x^2 + 2x + 7 and g(x) = x^2 + 9x + 6, what is f(g(x))?

To find f(g(x)), we need to substitute g(x) into the function f(x).

First, let’s rewrite the functions clearly:
f(x) = 2x² + 2x + 7
g(x) = x² + 9x + 6

Now we can substitute g(x) into f(x):
f(g(x)) = f(x² + 9x + 6)

We replace every x in f(x) with (x² + 9x + 6):

f(g(x)) = 2((x² + 9x + 6)²) + 2(x² + 9x + 6) + 7

Now we need to simplify this further. First, calculate (x² + 9x + 6)²:

(x² + 9x + 6)² = x^4 + 18x^3 + 117x^2 + 108x + 36 (using the formula (a + b + c)²)

Substituting back into f(g(x)):
f(g(x)) = 2(x^4 + 18x^3 + 117x^2 + 108x + 36) + 2(x² + 9x + 6) + 7

Now, distribute the 2:

f(g(x)) = 2x^4 + 36x^3 + 234x^2 + 216x + 72 + 2x² + 18x + 12 + 7

Combine like terms:

f(g(x)) = 2x^4 + 36x^3 + 236x^2 + 234x + 91

Thus, f(g(x)) simplifies to 2x^4 + 36x^3 + 236x^2 + 234x + 91.

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