Identify the values that create ordered pairs that are solutions to the equation 3x + 5y = 205y + x^2

To find the ordered pairs  (x, y)  that are solutions to the equation 3x + 5y = 205y + x^2, we first need to rearrange the equation into a standard form.

Starting from:

3x + 5y = 205y + x2

we can move all terms to one side:

x2 - 3x + 200y = 0

This looks like a quadratic equation in terms of x. To find the values of y that yield integer solutions for x, we can use the discriminant of this quadratic equation. The discriminant is given by the formula:

D = b2 – 4ac

For our equation:

  • a = 1
  • b = -3
  • c = 200y

Now substituting these into the discriminant formula:

D = (-3)2 - 4(1)(200y) = 9 - 800y

For the quadratic to have real solutions, the discriminant must be greater than or equal to zero:

9 - 800y 6 0

Solving for y:

800y  9
y  rac{9}{800}

This means y can take on values equal to or less than 0.01125. However, we are often looking for integer values, so the only integer value for y that fulfills this condition is:

  • y = 0

Now, substituting y = 0 back into our rearranged equation to solve for x gives:

x2 - 3x = 0

Factoring out x:

x(x - 3) = 0

This results in:

  • x = 0
  • x = 3

Thus, we can form the following ordered pairs that satisfy the original equation:

  • (0, 0)
  • (3, 0)

In conclusion, the values that create ordered pairs that are solutions to the equation are (0, 0) and (3, 0).

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