To transcribe the given DNA sequence into mRNA, we need to follow base pairing rules. DNA has the base pairs: A (adenine) pairs with U (uracil) in RNA, T (thymine) pairs with A, C (cytosine) pairs with G (guanine), and G pairs with C.
Given the DNA sequence: ccg tta tag gga aaa ccc gac ctt tca atc, we will transcribe it into mRNA starting from the 5′ end (the left-hand side) to the 3′ end.
The transcription process involves replacing each base in the DNA template strand with its complementary RNA base:
- c -> g
- c -> g
- g -> c
- t -> a
- t -> a
- a -> u
- g -> c
- t -> a
- a -> u
- g -> c
- g -> c
- g -> c
- a -> u
- a -> u
- a -> u
- c -> g
- c -> g
- c -> g
- g -> c
- a -> u
- c -> g
- c -> g
- t -> a
- t -> a
- c -> g
- a -> u
- t -> a
- c -> g
Based on these pairings, the transcribed mRNA sequence is: ggc aa ucc ccu uuu ggg cug gaa agu uag
So, the final mRNA sequence transcribed from the given DNA sequence is ggc aa ucc ccu uuu ggg cug gaa agu uag.