To solve the system of equations given by 2y = 6 and 3x + 6y = 18, we will first isolate the variables in these equations.
Step 1: Solve the first equation for y.
The first equation is:
2y = 6
To find y, we divide both sides by 2:
y = 6 / 2 = 3
So, now we know y = 3.
Step 2: Substitute y into the second equation.
The second equation is:
3x + 6y = 18
Substituting y = 3 into this equation:
3x + 6(3) = 18
3x + 18 = 18
Step 3: Solve for x.
Now, we subtract 18 from both sides:
3x = 18 - 18
3x = 0
Now, divide by 3:
x = 0
Conclusion:
The solution to the system of equations is x = 0 and y = 3.