How to Prepare 100 mL of a 6.0 M HCl Solution

To prepare 100 mL of a 6.0 M hydrochloric acid (HCl) solution, you need to understand the relationship between molarity, volume, and the amount of solute required. Molarity (M) is a way to express concentration, indicating the number of moles of solute per liter of solution.

Here’s a step-by-step guide to help you prepare this solution:

  1. Calculate the number of moles needed:

    First, you need to determine how many moles of HCl you require. Molarity (M) = moles of solute / volume of solution (L). Since you want 100 mL (or 0.1 L) of a 6.0 M solution:

    Number of moles = Molarity × Volume = 6.0 moles/L × 0.1 L = 0.6 moles

  2. Determine the mass of HCl required:

    Next, find the mass of HCl corresponding to 0.6 moles. The molecular weight of HCl is approximately 36.46 g/mol.

    Mass = moles × molecular weight = 0.6 moles × 36.46 g/mol = 21.876 g

  3. Measure the concentrated HCl:

    Concentrated hydrochloric acid usually has a molarity of about 12 M. To find out how much concentrated HCl you need to achieve 0.6 moles, use the formula:

    Volume (L) = moles / Molarity = 0.6 moles / 12 M = 0.05 L or 50 mL

  4. Prepare the solution:

    Take 50 mL of concentrated HCl and carefully dilute it with distilled water to a total volume of 100 mL. Always add acid to water, not the other way around, to ensure safety and prevent dangerous splashing.

  5. Final check:

    After diluting, ensure that the final volume is 100 mL. You now have a 6.0 M HCl solution ready to use.

Always handle HCl with care, wearing appropriate protective equipment, such as gloves and goggles, as it is corrosive and can cause severe burns.

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