To find the critical points and inflection points of the function f(x) = x^5 – 70x^3 + 13, we need to use derivatives.
Step 1: Find the first derivative
The first derivative, f'(x), helps us locate the critical points, where the function could have maxima, minima, or horizontal tangents:
f'(x) = 5x^4 - 210x^2
Step 2: Set the first derivative to zero
Next, we find where the first derivative is equal to zero:
5x^4 - 210x^2 = 0
Factoring out the common terms:
5x^2(x^2 - 42) = 0
This yields:
x^2 = 0 or x^2 - 42 = 0
So, we find:
x = 0 or x = ±√42
Step 3: Find the second derivative
The second derivative, f”(x), is necessary for determining the inflection points:
f''(x) = 20x^3 - 420x
Step 4: Set the second derivative to zero
To locate the inflection points, we set the second derivative to zero:
20x^3 - 420x = 0
Factoring out the common terms gives:
20x(x^2 - 21) = 0
This results in:
x = 0 or x^2 - 21 = 0
So, we find:
x = 0 or x = ±√21
Summary
In summary, the critical points of the function occur at:
- x = 0
- x = √42
- x = -√42
And the inflection points occur at:
- x = 0
- x = √21
- x = -√21