To draw the Lewis structure for Br2 and HBr, follow these steps:
Br2 (Bromine Gas)
1. Count the total number of valence electrons: Bromine (Br) is in Group 7, so each Br atom has 7 valence electrons. Since there are two Br atoms, the total number of valence electrons is 7 + 7 = 14.
2. Draw the skeletal structure: Place the two Br atoms next to each other.
3. Connect the atoms with a single bond: This uses 2 electrons, leaving 12 electrons.
4. Distribute the remaining electrons: Place 6 electrons around each Br atom to complete their octets.
5. Check the octet rule: Each Br atom should have 8 electrons around it, satisfying the octet rule.
HBr (Hydrogen Bromide)
1. Count the total number of valence electrons: Hydrogen (H) has 1 valence electron, and Bromine (Br) has 7. The total is 1 + 7 = 8 valence electrons.
2. Draw the skeletal structure: Place the H atom next to the Br atom.
3. Connect the atoms with a single bond: This uses 2 electrons, leaving 6 electrons.
4. Distribute the remaining electrons: Place the remaining 6 electrons around the Br atom to complete its octet.
5. Check the octet rule: The Br atom should have 8 electrons around it, and the H atom should have 2 electrons, satisfying the duet rule for hydrogen.
By following these steps, you can accurately draw the Lewis structures for Br2 and HBr.