How to Convert the Equation x² + y² + 8x + 22y + 37 = 0 to Standard Form?

To convert the given equation into standard form, we need to rearrange it and complete the square for both the x and y terms.

The equation is:

x² + y² + 8x + 22y + 37 = 0

First, let’s move the constant term to the other side:

x² + y² + 8x + 22y = -37

Next, let’s group the x terms and the y terms:

(x² + 8x) + (y² + 22y) = -37

Now, we need to complete the square for the x terms and the y terms.

For the x terms, x² + 8x:

  • Take half of 8, which is 4, and square it to get 16.
  • Add and subtract 16:

(x² + 8x + 16 – 16) = (x + 4)² – 16

For the y terms, y² + 22y:

  • Take half of 22, which is 11, and square it to get 121.
  • Add and subtract 121:

(y² + 22y + 121 – 121) = (y + 11)² – 121

Putting it all back together, we can rewrite our equation:

(x + 4)² – 16 + (y + 11)² – 121 = -37

Now simplify this:

(x + 4)² + (y + 11)² – 137 = -37

Adding 137 to both sides gives us:

(x + 4)² + (y + 11)² = 100

Now, the equation is in standard form:

(x + 4)² + (y + 11)² = 10²

This represents a circle with center at (-4, -11) and a radius of 10.

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