How many ways can a committee of 4 be selected from a club with 12 members?

To calculate the number of ways to select a committee of 4 members from a club of 12, we use the combination formula. Combinations are used here because the order of selection does not matter.

The formula for combinations is given by:

C(n, k) = n! / (k! * (n – k)!)

Where:

  • n is the total number of items (in this case, members in the club).
  • k is the number of items to choose (the members on the committee).
  • ! represents factorial; for example, 5! = 5 × 4 × 3 × 2 × 1 = 120.

Substituting the values into the combination formula, we have:

C(12, 4) = 12! / (4! * (12 – 4)!)

This simplifies to:

C(12, 4) = 12! / (4! * 8!)

Calculating the factorials:

12! = 12 × 11 × 10 × 9 × 8!

Hence, the equation becomes:

C(12, 4) = (12 × 11 × 10 × 9 × 8!) / (4! × 8!)

We can cancel out the 8! in the numerator and denominator:

C(12, 4) = (12 × 11 × 10 × 9) / 4!

Now, calculating 4!:

4! = 4 × 3 × 2 × 1 = 24

Now plug this back into our equation:

C(12, 4) = (12 × 11 × 10 × 9) / 24

Calculating the numerator:

12 × 11 = 132

132 × 10 = 1320

1320 × 9 = 11880

Now dividing by 24:

11880 / 24 = 495

So, the total number of ways to select a committee of 4 from the club of 12 members is 495.

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