In CH3COOH, also known as acetic acid, we can determine the number of sigma and pi bonds by analyzing its structure.
The molecular structure of acetic acid is as follows:
- The carbon atom in the methyl group (CH3) is bonded to three hydrogen atoms by single bonds. These are all sigma bonds.
- The carbon atom in the carboxyl group (COOH) is double-bonded to an oxygen atom and single-bonded to a hydroxyl group (OH). The double bond consists of one sigma bond and one pi bond.
- The oxygen atom in the hydroxyl group is bonded to a hydrogen atom by a single bond, which is a sigma bond.
To summarize:
- CH3 group contributes: 3 sigma bonds.
- COOH group contributes: 1 sigma bond (C-O), 1 pi bond (C=O), and 1 sigma bond (O-H).
Now, adding them up:
- Total sigma bonds: 3 (from CH3) + 2 (1 from C=O and 1 from O-H) = 5 sigma bonds.
- Total pi bonds: 1 (from the C=O double bond).
Therefore, in CH3COOH, there are a total of 5 sigma bonds and 1 pi bond.