To determine the mass in grams of 7.20 moles of N₂O₃, we first need to find the molar mass of N₂O₃.
N₂O₃ consists of 2 nitrogen (N) atoms and 3 oxygen (O) atoms. The atomic weights of nitrogen and oxygen from the periodic table are approximately:
- Nitrogen (N): 14.01 g/mol
- Oxygen (O): 16.00 g/mol
Now, we can calculate the molar mass of N₂O₃ as follows:
- Molar mass of N₂O₃ = (2 × 14.01 g/mol) + (3 × 16.00 g/mol)
- Molar mass of N₂O₃ = 28.02 g/mol + 48.00 g/mol
- Molar mass of N₂O₃ = 76.02 g/mol
Next, we multiply the number of moles (7.20 moles) by the molar mass (76.02 g/mol) to find the total mass in grams:
- Mass = moles × molar mass
- Mass = 7.20 moles × 76.02 g/mol
- Mass ≈ 547.54 grams
Therefore, the mass of 7.20 moles of N₂O₃ is approximately 547.54 grams.