How many grams are in 4.5 moles of Li2O?

To determine the mass of 4.5 moles of Li₂O, we first need to know the molar mass of lithium oxide (Li₂O).

Lithium (Li) has an atomic mass of approximately 6.94 g/mol, and oxygen (O) has an atomic mass of approximately 16.00 g/mol. Therefore, the calculation for the molar mass of Li₂O is as follows:

• Molar mass of Li₂O = (2 × 6.94 g/mol) + (1 × 16.00 g/mol)
• Molar mass of Li₂O = 13.88 g/mol + 16.00 g/mol = 29.88 g/mol

Now that we have the molar mass, we can find the mass of 4.5 moles of Li₂O by using the formula:

Mass = number of moles × molar mass

Substituting in our values:

Mass = 4.5 moles × 29.88 g/mol = 134.46 grams

Therefore, there are approximately 134.46 grams in 4.5 moles of Li₂O.