How many atoms of iron are in 0.750 moles of the compound iron(III) oxide?

To determine how many atoms of iron are in 0.750 moles of iron(III) oxide (Fe₂O₃), we first need to understand the composition of the compound. Iron(III) oxide is made up of two iron (Fe) atoms and three oxygen (O) atoms for every formula unit of Fe₂O₃.

Since each formula unit of iron(III) oxide contains 2 atoms of iron, we can calculate the total number of iron atoms in 0.750 moles of Fe₂O₃ as follows:

Step 1: Find the number of iron atoms per mole of Fe₂O₃.

1 mole of Fe₂O₃ contains 2 moles of iron atoms.

Step 2: Calculate the total moles of iron in 0.750 moles of Fe₂O₃.

Total moles of iron = 0.750 moles of Fe₂O₃ × 2 moles of Fe = 1.500 moles of Fe.

Step 3: Convert moles of iron to atoms.

Using Avogadro’s number (6.022 x 10²³ atoms/mole), we can find the number of atoms:

Total atoms of Fe = 1.500 moles of Fe × 6.022 x 10²³ atoms/mole = 9.033 x 10²³ atoms of Fe.

Conclusion: Therefore, in 0.750 moles of iron(III) oxide, there are approximately 9.033 x 10²³ atoms of iron.