How many atoms of hydrogen (H) are present on both sides of the equation 3H2 + N2 → 2NH3?

In the given chemical equation 3H₂ + N₂ → 2NH₃, we need to count the number of hydrogen atoms on both sides of the equation.

On the reactant side:

• The term 3H₂ indicates that there are 3 molecules of hydrogen gas. Since each molecule of H₂ contains 2 hydrogen atoms, we calculate: 3 × 2 = 6 hydrogen atoms.

On the product side:

• The term 2NH₃ indicates that there are 2 molecules of ammonia. Each molecule of NH₃ contains 3 hydrogen atoms, so we calculate: 2 × 3 = 6 hydrogen atoms.

Therefore, on both sides of the equation, we have a total of 6 hydrogen atoms. This shows that the equation is balanced in terms of hydrogen atoms.