How Does the Format Ion HCO2 Form Resonance Structures? Draw Lewis Structures and Show the Formal Charges for the Two Resonance Forms.

The format ion, HCO2, is a simple carboxylate anion that exhibits resonance. To draw the Lewis structures and show the formal charges, we need to start with the basic valence structures of the molecule.

1. **First Resonance Structure**: In the first structure, the negative charge is located on one of the oxygen atoms. The Lewis structure can be represented as:

    O
    ||
H -- C -- O-

In this structure, the carbon atom is single bonded to one oxygen (O) and double bonded to another oxygen. The formal charge can be calculated as follows:

  • For Carbon (C): 4 (valence electrons) – 0 (non-bonding electrons) – 4/2 (bonding electrons) = 0
  • For Oxygen (with double bond): 6 (valence electrons) – 4 (non-bonding electrons) – 4/2 (bonding electrons) = 0
  • For Oxygen (with single bond): 6 (valence electrons) – 6 (non-bonding electrons) – 2/2 (bonding electrons) = -1

So the formal charges for this resonance structure are: C = 0, O = 0 (double-bonded), and O = -1 (single-bonded).

2. **Second Resonance Structure**: In the second structure, we can move the double bond between carbon and oxygen over to the other oxygen. The new structure looks like this:

   O-
   ||
H -- C -- O

Here, the formal charges are recalculated:

  • For Carbon (C): 0 (as previously calculated)
  • For Oxygen (with double bond): 0 (as previously calculated)
  • For Oxygen (now with single bond): -1 (as previously calculated)

So in the second resonance structure, the formal charges remain the same: C = 0, O = 0 (single-bonded) and O = -1 (double-bonded).

Therefore, the format ion HCO2 has two resonance forms, and in both forms, the total charge is conserved, illustrating the stability of the molecule through resonance.

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