How do you use the discriminant to find the number of real solutions of the following quadratic equation 2x² + 4x = 0?

To determine the number of real solutions for the quadratic equation 2x² + 4x = 0, we can use the discriminant method. A quadratic equation is generally expressed in the form ax² + bx + c = 0, where a, b, and c are constants.

In our equation, we can rewrite it in standard form:

2x² + 4x + 0 = 0

From this equation, we can identify:

  • a = 2
  • b = 4
  • c = 0

The discriminant D is calculated using the formula:

D = b² – 4ac

Now, substituting the values of a, b, and c into the discriminant formula:

D = (4)² – 4(2)(0)

Calculating this gives:

D = 16 – 0 = 16

Now, we interpret the value of the discriminant:

  • If D > 0, there are two distinct real solutions.
  • If D = 0, there is exactly one real solution (a repeated solution).
  • If D < 0, there are no real solutions (the solutions are complex).

Since in our case D = 16, which is greater than zero, we conclude that there are two distinct real solutions for the quadratic equation 2x² + 4x = 0.

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