To factor the expression 27x3 – 8, we can recognize that both terms are perfect cubes. The first term, 27x3, can be rewritten as (3x)3, and the second term, 8, can be rewritten as 23. This gives us the difference of cubes formula, which states:
a3 – b3 = (a – b)(a2 + ab + b2)
In our case, a is 3x and b is 2. Plugging these values into the formula:
- a – b: 3x – 2
- a2: (3x)2 = 9x2
- ab: (3x)(2) = 6x
- b2: 22 = 4
Now we can assemble the factored form:
27x3 – 8 = (3x – 2)(9x2 + 6x + 4)
This gives us the completely factored form of the original expression.