How do I write the quadratic function in vertex form for y = x² + 4x + 7?

To convert the quadratic function y = x² + 4x + 7 into vertex form, we need to complete the square.

Starting with the given equation:

y = x² + 4x + 7

First, we focus on the x² + 4x part. To complete the square, we look for a number that, when added and subtracted inside the equation, will allow us to form a perfect square trinomial.

Take half of the coefficient of x, which is 4. Half of 4 is 2, and squaring it gives us 4.

Now, we rewrite the equation:

y = (x² + 4x + 4) – 4 + 7

The expression in parentheses (x² + 4x + 4) can be factored as (x + 2)².

Thus, we can rewrite the function as:

y = (x + 2)² – 4 + 7

Simplifying gives us:

y = (x + 2)² + 3

Now we have the quadratic function in vertex form:

y = (x + 2)² + 3

The vertex of this parabola is at the point (-2, 3), which is derived from the form (x – h)² + k where (h, k) is the vertex.

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