How can Ramona create a 10 ml of a 30% saline solution using 50% and 25% saline solutions?

To create a 10 ml solution of 30% saline, Ramona needs to mix certain amounts of the 50% saline solution and the 25% saline solution. We can use the concept of alligation to determine the correct proportions.

First, we denote:

  • x: the amount of 50% saline solution needed (in ml)
  • y: the amount of 25% saline solution needed (in ml)

Since the total volume of the solution must be 10 ml, we have:

x + y = 10

Next, we need the final concentration to be 30% saline. The equation for the salt concentration will be:

0.50x + 0.25y = 0.30(10)

Which simplifies to:

0.50x + 0.25y = 3

Now we have a system of two equations:

  1. x + y = 10
  2. 0.50x + 0.25y = 3

We can solve these equations step by step. From the first equation, we can express y in terms of x:

y = 10 – x

Substituting y into the second equation gives us:

0.50x + 0.25(10 – x) = 3

Expanding this, we find:

0.50x + 2.5 – 0.25x = 3

Combine like terms:

0.25x + 2.5 = 3

Now, isolate x:

0.25x = 3 – 2.5

0.25x = 0.5

x = 0.5 / 0.25

x = 2

Now substitute x back into the first equation to solve for y:

y = 10 – 2

y = 8

Thus, Ramona needs to mix:

  • 2 ml of the 50% saline solution
  • 8 ml of the 25% saline solution

By mixing 2 ml of the 50% saline solution and 8 ml of the 25% saline solution, she will successfully create 10 ml of a 30% saline solution.

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