Give the Lewis structures of the following neutral atoms: a) B, b) Se, c) Br

To illustrate the Lewis structures for the neutral atoms boron (B), selenium (Se), and bromine (Br), we first need to consider the number of valence electrons each atom has:

  • Boron (B): Boron is in group 13 of the periodic table, which means it has 3 valence electrons. The Lewis structure is represented by placing the three electrons around the chemical symbol:
  • Lewis Structure: Lewis structure of Boron
  • Selenium (Se): Selenium is in group 16 and has 6 valence electrons. Its Lewis structure shows these electrons around the symbol:
  • Lewis Structure: Lewis structure of Selenium
  • Bromine (Br): Bromine is in group 17 and possesses 7 valence electrons. The structure illustrates these electrons:
  • Lewis Structure: Lewis structure of Bromine

In summary, each Lewis structure visually represents the valence electrons of the respective neutral atom, providing insights into their bonding behavior and chemical properties.

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