Find the equation of the plane whose x intercept, y intercept, and z intercept are 2, 3, and 1 respectively.

To find the equation of a plane given its intercepts on the x, y, and z axes, we can use the intercept form of the equation of a plane. The general form is:

1/x + 1/y + 1/z = 1

Where:

  • x-intercept = 2
  • y-intercept = 3
  • z-intercept = 1

Substituting the intercept values into the equation:

1/2 + 1/3 + 1/1 = 1

To combine these fractions, we first find a common denominator, which is 6:

3/6 + 2/6 + 6/6 = 1

This simplifies to:

11/6 = 1

Now, we can write the equation of the plane:

(x/2) + (y/3) + (z/1) = 1

To tidy it up, we can multiply through by 6 to eliminate the fractions:

3x + 2y + 6z = 6

Thus, the equation of the plane is:

3x + 2y + 6z = 6

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