Find the derivative of the given function sin(3x^5)

To find the derivative of the function sin(3x5), we will use the chain rule. The chain rule states that the derivative of a composite function f(g(x)) is f'(g(x)) * g'(x).

In our case, let:

  • u = 3x5
  • f(u) = sin(u)

Now, we need to find the derivatives of f(u) and u:

  • f'(u) = cos(u)
  • u’ = 15x4 (using the power rule)

Now, we can apply the chain rule:

Therefore, the derivative of sin(3x5) is:

cos(3x5) * 15x4

This simplifies to:

15x4 * cos(3x5)

In conclusion, the derivative of sin(3x5) is 15x4 * cos(3x5).

More Related Questions