Find the area of a parallelogram with sides of 6 and 12 and an angle of 60°

To find the area of a parallelogram, we can use the formula:

Area = base × height

However, since we have the lengths of the sides and the angle between them, we can also apply the formula:

Area = a × b × sin(θ)

Where:

  • a = length of one side (6 units)
  • b = length of the adjacent side (12 units)
  • θ = angle between the two sides (60°)

Now, plugging in the values, we get:

Area = 6 × 12 × sin(60°)

We know that sin(60°) = √3/2. Substituting this value into our equation gives:

Area = 6 × 12 × (√3/2)

Area = 72 × (√3/2)

Area = 36√3 square units.

Thus, the area of the parallelogram is approximately 62.35 square units, when we calculate 36 times the approximate value of √3 (which is about 1.732).

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