Find cot x if sin x cot x csc x = √2

To find cot x given the equation sin x cot x csc x = √2, we can start by using the definitions of the trigonometric functions involved.

First, we know that:

  • csc x is defined as 1/sin x
  • cot x is defined as cos x/sin x

Substituting these definitions into the equation:

sin x (cos x/sin x) (1/sin x) = √2

This simplifies to:

cos x / sin x = √2

Thus, we have:

cot x = √2

Now, we have found that:

  • cot x = √2

This means that in a right triangle where the angle x is involved, the adjacent side is √2 times the opposite side. Therefore, we can conclude that the ratio of the adjacent side to the opposite side for this angle x is √2, which satisfies the equation provided.

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