To find the volume occupied by 30.0 grams of ethylene glycol, we can use the formula for density:
Density (Specific Gravity) = Mass / Volume
Given that ethylene glycol has a specific gravity of 1.11, we can relate this to its density in grams per cubic centimeter (g/cm³). Since the specific gravity is the ratio of the density of a substance to the density of water (which is 1 g/cm³), we can say:
Density of Ethylene Glycol = 1.11 g/cm³
Now, we can rearrange the density formula to solve for volume:
Volume = Mass / Density
We have:
- Mass = 30.0 grams
- Density = 1.11 g/cm³
Now, substituting these values into the volume formula:
Volume = 30.0 grams / 1.11 g/cm³
This gives us:
Volume ≈ 27.03 cm³
Therefore, the volume occupied by 30.0 grams of ethylene glycol is approximately 27.03 cubic centimeters.