Draw the Lewis structure of the conjugate acid of hydrogen sulfide (HS)

The conjugate acid of hydrogen sulfide (HS) is hydrosulfuric acid (H₂S). To draw its Lewis structure, follow these steps:

1. Count the total number of valence electrons: Hydrogen has 1 valence electron, and sulfur has 6. Therefore, for H₂S:
• 2 (from H) + 6 (from S) = 8 valence electrons
2. Determine the central atom: Sulfur is less electronegative than hydrogen, making it the central atom.
3. Place hydrogen atoms around sulfur: Draw sulfur in the center with the two hydrogen atoms bonded to it.
4. Form the bonds: Each H atom forms a single bond with the S atom, using 2 electrons for each bond.
• This uses 4 electrons out of the total 8.
5. Distribute the remaining electrons: There are 4 electrons left, which can be placed as lone pairs on the sulfur atom.
6. Final structure: The Lewis structure is:

  H
   |
H - S
   |
  :

In this structure, sulfur shares one of its six valence electrons with each hydrogen, forming two bonds, and retains two lone pairs. This configuration satisfies the octet rule for sulfur and the duet rule for hydrogen.