Draw the electron dot structure for each of the following atoms: a) Se b) P c) C d) I

To draw the electron dot structure, also known as Lewis dot structure, for each of the given atoms, we need to consider the number of valence electrons each atom has.

a) Selenium (Se)

Selenium is in group 16 of the periodic table and has 6 valence electrons. The electron dot structure will have 6 dots arranged around the symbol ‘Se’:

   ..
  :Se:
   ..

b) Phosphorus (P)

Phosphorus is in group 15 and has 5 valence electrons. Its electron dot structure will have 5 dots around the symbol ‘P’:

   .
  :P:
   .

c) Carbon (C)

Carbon is in group 14, which means it has 4 valence electrons. The electron dot structure for carbon will look like this:

   .
  :C:
   .

d) Iodine (I)

Iodine is in group 17 and has 7 valence electrons. The electron dot structure will have 7 dots around the ‘I’:

   ...
  :I:
   ...

In summary, the number of dots represents the valence electrons, and this helps in understanding how these atoms bond with others.

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