Draw the Electron Configuration of a Ground State Sulfur Atom (Z = 16) and Explain the Spin Multiplicity

The electron configuration of a ground state sulfur atom (atomic number 16) can be expressed as:

1s² 2s² 2p⁶ 3s² 3p⁴

This configuration indicates that the sulfur atom has a total of 16 electrons distributed among its orbitals. Breaking it down:

  • The first shell (1s) holds 2 electrons.
  • The second shell consists of 2 electrons in the 2s orbital and 6 electrons in the 2p orbitals, making a total of 8 electrons.
  • The third shell has 2 electrons in the 3s orbital and 4 electrons in the 3p orbital.

When visualizing the electron spins in the ground state configuration, we generally follow the Pauli exclusion principle and Hund’s rule:

  • Each orbital can hold a maximum of 2 electrons with opposite spins.
  • In the 3p orbitals, the four electrons will arrange such that one electron will occupy each of the three p orbitals (3p) before pairing occurs, resulting in two of the p orbitals containing paired spins.

To illustrate, the 3p orbitals can be drawn as:

3p: ↑↓  ↑  ↑

As for the spin multiplicity, it is determined using the formula:

Spin Multiplicity = 2S + 1

where S is the total number of unpaired electrons. In sulfur, the 3p orbital configuration shows two unpaired electrons (the two single arrows in the orbital distribution). Therefore:

  • S = 1 (since there are 2 unpaired electrons),
  • Spin Multiplicity = 2(1) + 1 = 3.

In summary, a ground state sulfur atom has an electron configuration of 1s² 2s² 2p⁶ 3s² 3p⁴, with a spin multiplicity of 3.

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