To determine the value of 3c3, we will use the formula for combinations, which is given by:
C(n, r) = n! / (r! * (n – r)!)
In this case, n is 3 and r is 3. Plugging these values into the formula, we get:
C(3, 3) = 3! / (3! * (3 – 3)!)
Now, calculating the factorials:
- 3! = 3 × 2 × 1 = 6
- (3 – 3)! = 0! = 1 (by definition)
Substituting back into the equation, we have:
C(3, 3) = 6 / (6 * 1) = 6 / 6 = 1
Thus, the value of 3c3 is 1.