Complete the following for the compound H2S: a) State its number of valence electrons, b) Draw its Lewis structure, c) Describe its VSEPR shape

a) Number of Valence Electrons:

Hydrogen (H) has 1 valence electron, and Sulfur (S) has 6 valence electrons. Since there are two hydrogen atoms in H₂S, the total number of valence electrons is:

2 (from H) + 6 (from S) = 8 valence electrons.

b) Lewis Structure:

The Lewis structure for H₂S is as follows:

Sulfur (S) is the central atom, with two hydrogen atoms bonded to it. Sulfur has two lone pairs of electrons. The structure can be represented as:

H – S – H

With the lone pairs on sulfur, the structure looks like:

H – S – H

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c) VSEPR Shape:

According to the VSEPR (Valence Shell Electron Pair Repulsion) theory, the shape of H₂S is bent or angular. This is because the two lone pairs of electrons on sulfur repel the bonding pairs, causing the hydrogen atoms to be pushed closer together, resulting in a bent shape. The bond angle is approximately 92°, which is less than the typical tetrahedral angle of 109.5° due to the lone pair repulsion.